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Contents:
Basics of Reinforced Concrete Slab Design
Slabs are generally designed on the assumption that they consists of a number of beams of breadth ‘one meter’.1. Effective Span of Slab
The effective span of a simply supported slab shall be taken as the lesser of the following:- Distance between the centers of bearings,
- Clear span plus effective depth
2. Thickness of Slab
The following table gives the maximum values of the ratio of span to depth.Type of slab | Ratio of span to depth |
Simply supported and spanning in one direction | 30 |
Continuous and spanning in one direction | 35 |
Simply supported and spanning in two directions | 35 |
Continuous and spanning in two directions | 40 |
Cantilever slabs | 12 |
3. Reinforcement for Slab
Minimum reinforcement in either direction shall be 0.15 percent of total cross-sectional area. Main reinforcement which is based on the maximum bending moment shall not be less than 0.15 per cent of the gross sectional area. The pitch of the main bars shall not exceed the following:- Three times the effective depth of slab, and
- 45 cm.
- Five times the effective depth of slab, and
- 45 cm.
4. Reinforcement Cover
The minimum cover to outside of main bars shall not be less than the following:- 15 mm and
- Diameter of the main bar.
5.  Concrete Slab Design Procedure
Steps to be followed in the design of slab- Assuming suitable bearings (not less than 10cm), find the span of the slab between the centers of bearings.
- Assume the thickness of slab (take 4 cm per metre run of the span).
- Find the effective span which is lesser of (i) distance between centres of bearings, and (ii) clear span and effective depth.
- Find the dead load and the live load per square meter of the slab.
- Determine the maximum bending moment for a one meter wide strip of the slab.
- Equate the balanced moment of resistance to the maximum bending moment
- Calculate the main reinforcement per metre width
Design of Continuous Slab
Suppose a slab is supported at the ends and also at intermediate points on beams, the maximum sagging and hogging moments to which the slab is subjected to due to uniformly distributed load, can be computed as follows: Let = intensity of dead load per square metre = intensity of live load per square metre. Bending moment due to dead load and live load may be taken as follows (IS: 456 – 2000) Bending Moment | At middle of end span | Over support | At middle of interior support | Over interior support |
Bending Moment due to dead load | ||||
Bending moment due to live load |