Derive the expression to find the distance and elevation of the object when the base of the object is inaccessible? Consider instruments and objects lies in the same vertical plane.
For deciding the location of headwork an irrigation system, you should have to follow points during the selection of location. Elevation of water should be in such a manner that the water will flow under the gravity force. All the construction materials should be available in the surrounding area. DRead more
For deciding the location of headwork an irrigation system, you should have to follow points during the selection of location.
- Elevation of water should be in such a manner that the water will flow under the gravity force.
- All the construction materials should be available in the surrounding area.
- Diversion head should be near the irrigation for irrigating area as possible and for keeping minimum canal length.
AdityaBhandakkar
When the base of the object is inaccessible we use an indirect method of surveying. A tachometer is used to measure the distance between the two points with the use of an analytical lens. There are two methods Stadia method: In this method diaphragm of the tachometer are provided with two stadia haiRead more
When the base of the object is inaccessible we use an indirect method of surveying.
A tachometer is used to measure the distance between the two points with the use of an analytical lens. There are two methods
D=(f/L)S + (f + d)
D=horizontal distance between tachometer and stadia rod.
f/L = multiplying constant
S= Staff Intercept
Elevation formula:
v = KSsin(2©)/2 + Ccos(2©)
© = Theta= Angle of elevation or depression.
K & C = Tachometric Constant
substance method and tangential method is also used to find the elevation between two points.
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