Cement volume is 0.25m3, Sand volume is 0.25m3, Coarse aggregate volume is 0.5m3. Concrete grade is M25.(mix proportion is 1:1:2). What will be the concrete volume in m3?
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Cement volume is 0.25m3, Sand volume is 0.25m3, Coarse aggregate volume is 0.5m3. Concrete grade is M25.(mix proportion is 1:1:2). What will be the concrete volume in m3?
Given,
M25, mix proportion would be- (1:1:2)
VC=0.25m3
VS=0.25m3
Va=0.5m3
Adding the mix ratios=1+1+2
=4
VConcrete=1/4* VC+1/4* VS+2/4* Va
=1/4*0.25m3+1/4*0.25m3+2/4*0.5m3
=0.375 m3
Gopal Mishra
Volume of fully compacted concrete is given by following formula:
where Vc is the volume of concrete. W, C, Fa and Ca are the masses of water, cement, fine aggregates and coarse aggregates respectively.
Density of cement = 1500 kg/m3, fine aggregates = 1700 kg/m3 and coarse aggregates = 1650 kg/m3.
So, Weight of cement C = 0.25 x 1500 = 375kg
Weight of Fine aggregates Fa = 0.25 x 1700 = 425 kg
Weight of Coarse aggregates Ca = 0.5 x 1650 = 825 kg
Consider w/c ratio as 0.45, so weight of water = 0.45×0.25×1000 = 112.5 L or kg
Sc, Sfa and Sca are the specific weight of cement, fine aggregates and coarse aggregates which are 3.15 for cement and 2.6 for fine and coarse aggregates.
Therefore, putting these values in the formula above, we get
Vc = (112.5/1000)+(375/(1000×3.15))+(425/(1000×2.6))+(825/(1000×2.6)) = 0.712m3
So, Volume of concrete = 0.712m3