How to calculate the quantity of water for a given mix concrete. As it would be required to calculate for mix 1:2:4.
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How to calculate the quantity of water for a given mix concrete. As it would be required to calculate for mix 1:2:4.
Obviously, water quantity cannot be decided based on the quantity mix design proportions only. There are other data which need to be known in order to be able to specify water content quantity for example, types of structural element, maximum aggregate size, and required workability. If these data are available, then the quantity of water can be easily computed from Table 6.3.3 of ACI 211.1-91.
Required slump can be determined based on the structural element type. Maximum aggregate size and slump value can be used to determine quantity of water for 1 meter cubic of concrete.
muganeza2016
Yes, thank you Mr. Madeh Izat Hamakareem for your good answer.
NARENDERSINGH
As per Is code 456-200 clauses 6.1.2
maximum free water cement ratio for M15(1:2:4) is 0.50
for 1 cubic metre concrete
1+2+4=7
cement content =1/7 *1 =0.1428 m3
density =mass/volume
density of cement =1440kg/m3 (note :- density of cement varies with grade and brand)
mass of cement =0.1428*1440=205.632 kg (note:- please consider minimum cement content also i.e. also given in clauses 6.1.2 of Is code)
w/c as per IS code is 0.50 for M15
w/c=0.50
water content=0.50*205.632=102.8 m3 =103 litre
Note:-w/c depends on various factors like moisture content of fine/coarse aggregate,workability …..
Vívèk Gúptã
it has a simple way to solve that.
The taken water ratio of your mix design (multiply)Weight of cement.
W/C*Quantity of cement= Quantity of water
chrisjackson
If we need to calculate Water quantity for concrete, first find the cement content for the volume. Therefore, Required amount of water = 0.5 X 50 kg = 25 litres / 50 kg cement bag. For Design mix, the W/C Ratio will depend upon the workability, strength requirements.
Poras Patel
Dear Sir
First of all you need to know the quantity of cement.
1:2:4 Means M15 Grade
Cement require for 01 Cu.m Concrete is:
Wet volume of concrete is 1.54 Cu.m = (1.54/1+2+4)*1 = 0.22 Cu.m
Now 0.22 Cu.m Cement = 0.22*1440 Kg/m3 (Density of cement) =316.80 kg cement = 316.80 kg
Now W/c Normally require for M15 Grade is 0.50
So water require: W/C = 0.50 =
C*0.50 = Water
316.80*0.50=Water
Water = 158.40 Litre/Cu.m
vihar varu
The quantity of water calculates the base one depend on the water-cement ratio.
W/C=AS PER IS CODE RATIO(DEPEND ON GRADE OF CONCRETE)
Seshachalam Chamarthy
Calculate the existing moisture content in the aggregates (fine & coarse) and it will be deducted from the water content, which is calculated from water cement ratio
Moisture content in Coarse aggregate – x1
Moisture content in fine aggregate – x2
Moisture content based on water cement ration (example -0.355) = 0.355*450kg/cum = 159.75
Net water content is = 159.75 – x1 – x2
chrisjackson
The mix 1:2:4 represents the M15 grade of concrete, which means the concrete formed with this ratio has a compressive strength of 15 kN/m^2. 1:2:4 represents the amount of cement, fine aggregate (sand) and coarse aggregate to be added during batching of concrete.
Calculation of Water Quantity for Concrete
If we need to calculate Water quantity for concrete, first find the cement content for the volume. Therefore, Required amount of water = 0.5 X 50 kg = 25 litres / 50 kg cement bag. For the Design mix, the W/C ratio will depend upon the workability, strength requirements.
vsandeep577@gmail.com
for Mix 1:2:4 water requirement would be-
Plain concrete(moderate)
The Minimum cement content for M15=240 kg/ m3
and min water cement ratio =water/cement =0.60
=water/240=0.60
Min water requirement for mix=240*.60=120 liters
It is also depend upon climate condition,method of mixing and the purpose of use.
wissam
Can you please tell me where you got the wet of concrete is 1.54 cu/m
Dhanya
The W/C ratio varies from 0.4 to 0.6 as per IS 10262(2009) for a normal mix
To calculate the amount of water required for a concrete mix, we need to calculate the quantity of cement required.
Assume the required amount of cement is 50kg
Amount of water required = W/C ratio x cement required.
= 0.5 x 50
= 25 litres/50kg
For the design mix, W/C ratio depends upon the workability and strength requirements.
dbnalawade
The accurate quantity of water for a mix depends your selection of water cement ratio, compressive strength, workability, durability, maximum nominal size of aggregate, grading,type of aggregates , absorption and the degree of control. The question of 1:2:4 could be on mix by volume or mass. W/C ratio is usually determined by mass.
IS:456 is s good code to follow for design a mix.
shankar
Actually water content is determined from the W/c ratio of different mixes as per IS 456:2000. but roughly for normal mix (1:2:4), we can calculate as
vol. of cement = 0.0354 cu.m
vol. of C.A+ F.A=2*0.0354+4*0.0354=0.211 cu.m
Vol. of water = 11.67 litre for 1 bag + 5% of total aggregate
= 11.67+(0.05*0.211)*1000=11.67+10.55= 22.22 litre
Here we have 1:2:4 mix is given, which is the standard ratio for M15 grade.
I do the calculation for 1 m3 concrete.
for cement content, c= 1/(1+2+4)= 1/7 m3
weight of cement = {1/7/(.035)}*50 = 204kg
total weight of cement for mix = 1.54*204 = 310.20kg
(total weight of cement for mix =310.20kg) >( minimum cement content – 300kg for moderate exposure condition)
<(maximum cement comntent -450kg)
for exact water content, we should know about exposure conditions, for different exposure conditions water content will be different. here I mention different exposure conditions with their maximum w/c ratio.
mild-.55
moderate – .50
sever – .45
very sever – .45
extreme – .40
I do the calculation for moderate exposure condition (you can do it for others exposure condition also, but the method will be the same. for other calculation you should check cement content for minimum and maximum cement content with different exposure condition)
w/c = .50
w = .5*310.20
w = 155.10 kg = 155.10 liter
so, water content for m15 grade with moderate exposure is 155.10 liter.
aviratdhodare
To calculate the amount of water required for a concrete mix, we need to calculate the quantity of cement required. Assume the required amount of cement is 50kg Amount of water required = W/C ratio x cement required. = 0.5 x 50 =25 kg or 25 lit
M 15 grade concrete
sanjaypakad
w/c ratio is the weight ratio of the quantity of water used and weight of cement used in a particular concrete mixture.
w/c ratio = (water weight)/(cement weight)
If you do not know what number to use for the (w/c) ratio, please refer to the standards (depending on the country you reside/ where you want to use the concrete) regarding the maximum limits on the w/c ratio.
Subash Pathak
1:2:4 i.e cement:sand: coarse aggregate ratio during the batching of concrete. for the quantity of water, first, find out cement content for the given volume.
lets cement content be x (kg)
then,
water requirement = x * 0.5 liters/ bag of cement
rawaa
it depend on the code of ACI 211.1-91
the water content depend on quantity of cement and many factors effect like size of aggregate and compressive strength that the concrete designed for.
Omprakash Dhawale
Sir,
With reference to the IS10262-2019 code, for 10mm aggregate sizes, the water content is 208Kg/ meter cube. Refer the attached table.
Preet Chovatiya
As we know 1:2:4 ratio is for M15 concrete. Generally Water quantity is calculated as per below formula:
Water Quantity=W/C ratio*Cement Quantity
Generally W/C ratio is lays between 0.4 to 0.6 as per IS 10262(2009).
Now first we have to assume cement quantity, so let’s assume cement quantity=50 KG and W/C ratio=0.5
Now let’s calculate water quantity for 50 KG cement.
Water Quantity=0.5*50=25 liter.